Now keep going, obeying, for increasing n, this rule:
• The nth point and the previous
n
- 1 points all lie in different
ths of the line. (All points
, for m = 0, 1, 2, . . . , n, are excluded.)
Got that? Here’s the question: how long can you keep this process going?
At first sight, the answer seems to be: as long as you wish. After all, you can divide the line into indefinitely ever finer pieces, and choose points in whichever of those are appropriate.
I really don’t expect you to get the correct answer here, but I don’t want to give it away immediately, so you’ll find it on page 336. It’s amusing to try placing the first five or six points. Even then, it’s not as easy as it sounds.
Chess in Flatland
In Flatland (page 255) the world is a plane and its inhabitants are geometric shapes. Flatlanders play their own versions of Spaceland games, and one of them is chess. The Flatland chessboard is eight cells long, and each player has three pieces: king, knight and rook, starting in the position shown.
Start of a game of Flatland chess.
The rules resemble those of Spaceland chess, bearing in mind the limitations of Flatland geometry. All three pieces can move to the left or to the right, if a suitable space is available. All moves must end either on an empty cell, or on a cell occupied by an enemy piece, which is then removed from the board - ‘taken’.
• A king (the piece with a cross on top) moves only one cell at a time, and cannot move into ‘check’ - a cell that is already threatened by the enemy.
• A knight (horse shape) moves by jumping over an adjacent cell, which may be empty or occupied, and landing on the one on its far side. So it ends up two cells away from where it started.
• A rook (castle shape) can move across any number of unoccupied cells.
If a player has no legal move available, the game is stalemate, and is a draw. If a player can threaten the opposing king, and the king cannot escape, that’s checkmate, and the game is won.
If White plays first, and both players adopt perfect strategy, who will win?
Answer on page 337
The Infinite Lottery
The Infinite Lottery involves infinitely many bags: one numbered 1, one numbered 2, one numbered 3, one numbered 4, and so on. Each bag contains infinitely many lottery balls with the corresponding number.
You are supplied with a large box. You may place any number of balls you like into this box, chosen from any of the bags. There is just one condition: the total number must be finite.
Now you are required to change the balls in the box. You must remove and discard one, and replace it by as many balls as you like that bear smaller numbers. For instance, if you discard a ball with the number 100 on it, you can add to the box 10 million balls with the number 99, 17 billion with the number 98, and so on. There is thus no upper limit to the number of balls that can replace that solitary number-100 ball.
You must keep doing this. At each stage you may replace the discarded ball by whichever combination of balls you wish, provided you make their number finite and make sure that they bear smaller numbers than the ball you discarded. If you remove a ball marked 1, you cannot replace it because there are no balls with smaller numbers on them.
If eventually you run out of balls and empty the box, you lose. If you keep removing balls for ever - that is, if you never run out of balls - then you win.
But can you win the infinite lottery? If so, how?
Answer on page 337
Ships That Pass ...
In the days when people crossed the Atlantic in passenger liners, a ship left London every day at 4.00 p.m. bound for New York, arriving exactly 7 days later.
Every day at the same instant (11.00 a.m. because of the time
difference) a ship left New York bound for London, arriving exactly 7 days later.
All ships followed the same route, deviating slightly to avoid collisions when they met.
How many ships from London does each ship sailing from New York encounter during its transatlantic voyage, not counting any that arrive at the dock just as they leave, or leave the dock just as they arrive?
Answer on page 339
The Largest Number Is Forty-Two
Mathematicians often use a technique called proof by contradiction. The idea is that to prove some statement true, you begin by assuming it to be false, and go on to derive various logical consequences. If any of these consequences leads to a logical impossibility - a contradiction - then your assumption that the statement is false cannot be correct. Therefore the statement is true.
You may have come across this by the name used in Euclid, which in Latin translation is reductio ad absurdum - reduction to the absurd.
For example, to prove that pigs don’t have wings, you first assume that they do, and deduce that pigs can fly. But we know that they can’t, so this is a logical impossibility. Therefore it is false that pigs don’t have wings, so they do.
Got that?
I will now use proof by contradiction to show that the largest whole number is 42.
Let n be the largest whole number, and suppose for a contradiction that n is not 42. Then n > 42, so (
n
- 42)
3
>0, which expands to give
n
3
- 126
n
2
+ 5,292
n
- 74,088 > 0
Adding n to each side,
n
3
- 126
n
2
+ 5,293
n
- 74,088 >
n
But the left-hand side is a whole number. Since it is greater than n, which we are assuming to be the largest whole number, we have derived a contradiction.
Therefore it is false that the largest whole number is not 42. So it is 42!
Clearly something is wrong here - but what?
Answer on page 339
A Future History of Mathematics
2087
| Fermat’s Lost Theorem is found again on the back of an old hymn-sheet in the Vatican secret archives.
|
2132
| A general definition of ‘life’ is formulated at the Intercontinental Congress of Biomathematicians.
|
2133
| Kashin and Chypsz prove that life cannot exist.
|
2156
| Cheesburger and Fries prove that at least one of Euler’s constant, the Feigenbaum number, and the fractal dimension of the universe is irrational.
|
2222
| The consistency of mathematics is established - it is that of cold sago pudding.
|
2237
| Marqès and Spinoza prove that the undecidability of the undecidability of the undecidability of the undecidability of the P=NP? problem is undecidable.
|
2238
| Pyotr-Jane Dumczyk disproves the Riemann hypothesis by showing that there exist at least 42 zeros σ + it of the zeta function with σ ≠ and t < exp exp exp exp exp ((π e +e π ) log 42).
|
2240
| Fermat’s Lost Theorem is lost again.
|
2241
| Sausage conjecture proved in all dimensions except 5, with the possible exception of the 14- dimensional case, where the proof remains controversial since it seems too easy.
|
2299
| Contact is made with aliens from Grumpius, whose mathematics includes a complete classification of all possible topologies for turbulent flows, but has been stuck for the past five galactic revolutions because of an inability to solve the 1 + 1 = ? problem.
|
2299
| The solution of the 1 + 1 = ? problem by Martha Snodgrass, a six-year-old schoolgirl from Woking, ushers in a new age of Terran-Grumpian cooperation.
|
2300
| Formulation of Dilbert’s 744 problems at the Interstellar Congress of Mathematicians.
|
2301
| Grumpians depart, citing the start of the cricket season.
|
2408
| Riculus Fergle uses Grumpian orthocalculus to show that all of Dilbert’s problems are equivalent to each other, thereby reducing the whole of mathematics to a single short formula. *
|
2417
| The DNA-superstring computer Vast Intellect fails the Turing Test on a technicality but declares itself intelligent anyway.
|
2417
| Vaster Intellect invents the technique of human-assisted proof, and uses it to prove Fergle’s Final Formula, with the Dilbert problems as corollaries.
|
2417
| Even Vaster Intellect discovers inconsistencies in the operating system of the human brain, and all human-assisted proofs are declared invalid.
|
7999
| Grunt Snortsen invents counting on his toes; Reign of the Machines comes to an abrupt end.†
|
* The famous € ♋♍☾ 42 . Plus a constant.
|
† Snortsen had lost a toe in an encounter with a berserk cashregister.
|
11,868
| The Rediscovery of Mathematics, now in base 9.
|
0
| Reformation of the calendar.
|
1302*
| Fergle’s Final Formula is proved, correctly this time, and mathematics stops.
|
1302†
| Diculus Snergle asks what would happen if you allowed the arbitrary constant in Fergle’s Final Formula to be a variable, and mathematics starts up again.
|
Professor Stewart’s Superlative Storehouse of Sneaky Solutions and Stimulating Supplements
Wherein the perspicacious or perplexed reader may procure answers to those questions that are presently known to possess answers ... together with such gratuitous facts and fancies as may facilitate their further delectation and enlightenment.
Calculator Curiosity 1
(8×8) + 13 = 77
(8×88) + 13 = 717
(8×888) + 13 = 7117
(8×8888) + 13 = 71117
(8×88888) + 13 = 711117
(8×888888) + 13 = 7111117
(8×8888888) + 13 = 71111117
(8×88888888) + 13 = 711111117
Year Turned Upside Down
Past: 1961; Future: 6009.
If you insist on allowing a squiggle on the 7, amend these to 2007 and 2117.
Sixteen Matches